10y^2-1000=0

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Solution for 10y^2-1000=0 equation:



10y^2-1000=0
a = 10; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·10·(-1000)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*10}=\frac{-200}{20} =-10 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*10}=\frac{200}{20} =10 $

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